Source Code:
Solution:
– We take a Map, which’ll give me info about unique characters present, Map key will be character & value will be the occurrence of that character
– We’ll take a max_length variable, where we’ll store the solution
– we’ll take two variable start & end, which’ll point to 1st character in string initially
– Now we iterate the string & keep on putting character in map. If size of value is greater than K, then we decrease the character from start index. If occurrence becomes 0, we remove from map.
– max_length will be updated by end – start + 1
– At last we return, max_length as answer
Time Complexity: O(n)
Space Complexity: O(n)
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